question: a bullet of mass 10g moving with velocity of 400 m/s gets embedded in a freely suspended wooden block of mass 900g.What is the velocity acquired Von the block?

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6 hours!! this Frage would get closed.
fightxd posted Vor mehr als einem Jahr
 fightxd posted Vor mehr als einem Jahr
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Science Antwort

demi382 said:
answer:4.4m/s
reason: let the final velocity of the bullet embedded in it be v
according to the law of conservation of momentum,
total momentum before collision = total momentum after collision
= 0.001* 400+0.9*0/0.001 + 0.9 = 4/0.91 = 400/91 = 4.4 m/s
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correct answer but i can't belive that no one answered than Du , any way congratulations!
fightxd posted Vor mehr als einem Jahr
bahu said:
mass of bullet= 10 g = 0.01 kg
velocity of bullet=400 m/s
mass of wooden box= 900 g =0.9 kg
velocity of wooden block= ?

formula= Mb 1*Vb 1=Mb 2*Vb 2
0.01*400=0.9*Vb2
=0.01*400/0.9=4.4444444 m/s
ans=4.4 m/s
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